Unit 2 Capstone Review: Radicals, Conjugates, Solid Geometry, Linear Equations, and Slopes
Congratulations on completing Unit 2! In this comprehensive capstone review, we integrate all the essential concepts and computational methods mastered across the unit. We review: the algebraic laws of square and cube roots, simplification by extracting perfect powers, rationalizing binomial denominators using conjugate numbers, geometric applications on cubes, spheres, and cylinders, graphing linear equations ax + by = c using ordered pairs, determining intercepts with the coordinate axes, computing and interpreting slopes, verifying collinearity of points, and solving real-life rate-of-change word problems. This thorough synthesis ensures complete mathematical mastery for the standardized digital exams.
Radicals & Conjugates
- √(ab) = √a × √b | ³√(ab) = ³√a × ³√b.
- Conjugates: (√a + √b)(√a - √b) = a - b.
- Cube: V = s³, Area = 6s².
- Sphere: V = 4/3 π r³, Area = 4 π r².
- Cylinder: V = π r² h, Lat. Area = 2 π r h.
Linear Relations
ax + by = crepresents a straight line.- x-intercept: set y = 0 → (c/a, 0).
- y-intercept: set x = 0 → (0, c/b).
- x-axis: y = 0 | y-axis: x = 0.
- Passes through origin if c = 0.
Slope Matrix
m = (y&sub2; - y&sub1;) / (x&sub2; - x&sub1;).- Parallel lines: m&sub1; = m&sub2;.
- Perpendicular lines: m&sub1; × m&sub2; = -1.
- Horizontal: m = 0 | Vertical: undefined.
- Distance-time slope = velocity.
Comprehensive Diagnostic Problems:
Solution:
m = (7 - 3) / (2 - x) = 4 / (2 - x) = 2 → 2(2 - x) = 4 → 2 - x = 2 → x = 0.
Solution:
1. Volume of cylinder = π r² h = π (3)² (4) = 36π cm³.
2. Volume of sphere = 4/3 π R³ = 36π → R³ = 36 × (3/4) = 27.
3. Radius R = ³√27 = 3 cm.
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